Physics - Current Electricity Question with Solution | TestHub

Average power of an LCR circuit is $\mathrm{P}={\mathrm{E}}_{\mathrm{V}}{\mathrm{I}}_{\mathrm{v}}\cos \varphi .$ Maximum power is dissipated at resonance when ${\mathrm{X}}_{\mathrm{L}}={\mathrm{X}}_{\mathrm{C}}$. The resonance frequency is given by $v=\frac{1}{2\pi \sqrt{\mathrm{LC}}}$ $=\frac{1}{2\times 3.14\times \sqrt{25\times 10^{-3}\times 400\times 10^{-6}}}$ $=\frac{1}{2\times 3.14\times 5\times 20\times 10^{-5}\sqrt{10}}$ $=\frac{10^5}{3.14\times 200\sqrt{10}}$ $=\frac{10^3}{6.28\times \sqrt{10}}=\frac{159.2}{3.16}=50.31\mathrm{Hz}$