The resistance of a field coil measures 50Ω at 2 0 ∘ C and 65Ω at 7 0 ∘ C . The temperature coefficient of resistance is

The value of temperature coefficient of resistance is given by α = R 1 ( t 2 − t 1 ) R 2 − R 1 = 50 ( 70 − 20 ) 65 − 50 ( t 1 and t 2 are in ∘ C ) ⇒ α = 50 × 50 15 = 0.006/ ∘ C

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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityEquivalent ResistanceMedium2 minPYQ_2006

PhysicsMediumsingle choice

The resistance of a field coil measures $50Ω$ at $2 0^{\circ} C$ and $65Ω$ at $7 0^{\circ} C$ . The temperature coefficient of resistance is

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The value of temperature coefficient of resistance is given by $α = \frac{R _{2} - R _{1}}{R _{1} ( t _{2} - t _{1} )} = \frac{65 - 50}{50 ( 70 - 20 )} (t_{1} and t_{2} are in^{\circ} C) \Rightarrow α = \frac{15}{50 \times 50} = 0.006/^{\circ} C$

Stream:VITEEESubject:PhysicsTopic:Current ElectricitySubtopic:Equivalent Resistance

⏱ 2mℹ️ Source: PYQ_2006

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