In a Wheatstone's bridge, there resistances P , Q and R connected in the three arms and the fourth arm is formed by two resistances S 1 and S 2 connected in parallel. The condition for bridge

Question

In a Wheatstone's bridge, there resistances $P, Q$ and $R$ connected in the three arms and the fourth arm is formed by two resistances $S_{1}$ and $S_{2}$ connected in parallel. The condition for bridge to be balanced will be

Options:

Answer:

C

Solution:

$\frac{P}{Q} = \frac{R ( S _{1} + S _{2} )}{S _{1} S _{2}}$

TestHub · Accepted Answer

Q P ​ = S 1 ​ S 2 ​ R ( S 1 ​ + S 2 ​ ) ​

Physics - Current Electricity Question with Solution | TestHub

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