Physics - Current Electricity Question with Solution | TestHub

The resistance of each bulb is $\frac{V^2}{P}$ $=\frac{(200{)}^2}{60}\Omega$ when three bulbs are connected in series then equivalent resistance is $\frac{3\bullet (200{)}^2}{60}$ $\therefore$ Power $P=\frac{V^2}{R_{eq}}=20\mathrm{W}$