The current density at a point is J = ( 2 × 1 0 4 ) Am − 2 j ^ . Find the rate of charge flow (in A) through a cross sectional area S = ( 2 i ^ + 3 j ^ ) cm 2

I = J ⋅ S J = 2 × 1 0 4 j ^ A / m 2 S = ( 2 i ^ + 3 j ^ ) × 1 0 − 4 m 2 I = 6 A

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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityMicroscopicEasy2 minPDF

PhysicsEasynumerical

The current density at a point is $J = (2 \times 1 0^{4}) Am^{- 2} \hat{j}$ . Find the rate of charge flow (in A) through a cross sectional area $S = (2 \hat{i} + 3 \hat{j}) cm^{2}$

Answer:

6.00

Solution:

$I = J \cdot S$

$J = 2 \times 1 0^{4} \hat{j} A / m^{2}$

$S = (2 \hat{i} + 3 \hat{j}) \times 1 0^{- 4} m^{2}$

$I = 6 A$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Microscopic

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