A ring of mass 2 π kg and of radius 0.25 m is making 300 rpm about an axis through its centre perpendicular to its plane. The tension (in newtons) developed in the ring is : (take π 2 = 10 )

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As 2 T sin 2 θ ​ = dm ω 2 r (for small angle sin 2 θ ​ → 2 θ ​ ) but dm = ℓ m ​ θ r As ℓ = 2 π r ∴ T = m ω 2 r /2 π Put m = 2 π kg ω = 10 π radian / s and r = 0.25 m

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