Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionKinematicsMedium2 minQB

PhysicsMediummultiple choice

The 8-kg sack slides down the smooth ramp. If it has a speed of 1.5 m/s when $y = 0.2 m$ , choose the CORRECT option(s) :

Answer:

B, C

Solution:

$y = 0.2 e^{x}$ ; at $y = 0.2$ , $x = 0$ and $tan θ = 0.2$ : $sin θ = \frac{1}{26}$ , $cos θ = \frac{5}{26}$ .

Radius of curvature: $R = \frac{[ 1 + ( 0.2 ) ^{2} ] ^{3/2}}{0.2} = 5.3$ m.

$N = m g cos θ + \frac{m v ^{2}}{R} = 80 \times \frac{5}{26} + \frac{8 \times ( 1.5 ) ^{2}}{5.3} = 81.84$ N - (B)

Tangential acceleration $= g sin θ = 1.96$ m/s $^{2}$ - (C)

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Kinematics

⏱ 2mℹ️ Source: QB

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