In the given figure : (a) When particle strike the ground its angular velocity about 'O' is 16 1 rad/sec (b) When particle strike the ground its angular velocity about 'O' is 96 1 rad/sec (c) At t = 6 sec value of tangential acceleration is zero. (d) At t = 6 sec value of tangential acceleration is g downward.

Ans. (1) ω = R 100 s i n 3 7 ∘ At t = 6 , the particle is at its highest point. So a t = 0 .

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PhysicsCircular MotionMiscellaneousMedium2 minQB

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In the given figure :

(a) When particle strike the ground its angular velocity about 'O' is $\frac{1}{16}$ rad/sec

(b) When particle strike the ground its angular velocity about 'O' is

$\frac{1}{96}$ rad/sec

(d) At t = 6 sec value of tangential acceleration is g downward.

Answer:

Solution:

Ans. (1)

$ω = \frac{100 s i n 3 7 ^{\circ}}{R}$

At $t = 6$ , the particle is at its highest point.

So $a_{t} = 0$ .

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

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