Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionKinematicsEasy2 minQB

PhysicsEasysingle choice

Speed of a rotating particle in a circle of radius 4 m is $v = t^{2}$ , its acceleration after 2 s will be :-

Answer:

Solution:

Speed $v = t^{2}$ , so at $t = 2$ s: $v = 4$ m/s

Tangential acceleration $a_{t} = \frac{d v}{d t} = 2 t = 4 m/ s^{2}$

Centripetal acceleration $a_{c} = \frac{v ^{2}}{r} = \frac{16}{4} = 4 m/ s^{2}$

Net acceleration $= a_{t}^{2} + a_{c}^{2} = 16 + 16 = 42 m/ s^{2}$

Answer: (B)

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Kinematics

⏱ 2mℹ️ Source: QB

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