Physics - Circular Motion Question with Solution | TestHub
PhysicsCircular MotionDynamicsMedium2 minQB
PhysicsMediumnumerical range
A mass m = 0.3 kg is connected to a light but rigid rotating shaft by two strings. The mass moves in a horizontal circle of radius R = 0.2√3 m at constant speed. The shorter, horizontal string has breaking strength Tmax = 5.0√3 N. The longer string, which makes an angle θ = 30° to the vertical, is much stronger. [Take g = 10 m/s²]
The minimum number of revolutions per minute so that the shorter string remains taut.
Answer:
39.00
Solution:
Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Dynamics
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...