Physics - Circular Motion Question with Solution | TestHub

At A the tangential component is $g$ (gravity along the tangent) and the radial component is $\frac{v^2}{R}$ , so
$a_{net}=\sqrt{g^2+{\left(\frac{v^2}{R}\right)}^2}>g$ (Assertion true).
The Reason states exactly that the net acceleration is the resultant of the two components, which is why it exceeds $g$, so it explains the Assertion.