A particle is moving with a constant angular acceleration of 9 rad / s 2 in a circular path. At time t = 0 , particle was at rest. Find the time at which the magnitudes of centripetal acceleration and

Question

A particle is moving with a constant angular acceleration of $9 rad / s^{2}$ in a circular path. At time $t = 0$ , particle was at rest. Find the time at which the magnitudes of centripetal acceleration and tangential acceleration are equal.

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Answer:

A

Solution:

$R ω^{2} = R α,$
with $ω = α t$ ,
gives $(α t)^{2} = α$ ,
so $t = \frac{1}{α}$
$= \frac{1}{3} s$ .

TestHub · Accepted Answer

R ω 2 = R α , with ω = α t , gives ( α t ) 2 = α , so t = α ​ 1 ​ = 3 1 ​ s .

Physics - Circular Motion Question with Solution | TestHub

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