Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionKinematicsMedium2 min

PhysicsMediummultiple choice

A particle is projected making an angle $θ$ to horizontal as shown in figure :

Answer:

A, B, C, D

Solution:

At C point, $v = u cos θ$

$a = \frac{v ^{2}}{R} = \frac{u ^{2} cos ^{2} θ}{R} R = \frac{u ^{2} cos ^{2} θ}{a} = \frac{u ^{2} cos ^{2} θ}{g}$

at $A a_{N} = g cos θ$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Kinematics

⏱ 2m

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