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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionKinematicsHard2 minQB

PhysicsHardinteger

Two particles A and B perform circular motion as shown in diagram. The locations of the particles are shown at $t = 0$ . Find radius of curvature (in m ) of B as seen by A at $t = \frac{π}{2 ω} (R = 1 m)$

Answer:

Solution:

At $t = \frac{π}{2 ω}$ , relative speed of B w.r.t. A is $v_{re l} = 3 ω R$ .

Relative acceleration perpendicular to $v_{re l}$ : $a_{⊥} = ω^{2} R$ .

Radius of curvature: $ρ = \frac{v _{re l}^{2}}{a _{⊥}}$ $= \frac{9 ω ^{2} R ^{2}}{ω ^{2} R} = 9 R$

With $R = 1$ m: $ρ = 9$ m.

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Kinematics

⏱ 2mℹ️ Source: QB

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