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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionDynamicsMedium2 minQB

PhysicsMediuminteger

A 10 kg ball attached to the end of a rigid massless rod of length 1 m rotates at constant speed in a horizontal circle of radius 0.5 m and period $π /2 sec$ as in fig. The horizontal force exerted by rod (in N) on the ball is F. Fill F/16.

Answer:

Solution:

$ω = \frac{2 π}{T} = \frac{2 π}{π /2} = 4$ rad/s

Horizontal force from the rod provides the centripetal force: $F = m ω^{2} r = 10 \times 16 \times 0.5 = 80$ N

$\frac{F}{16} = 5$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Dynamics

⏱ 2mℹ️ Source: QB

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