Start Free Mock LoginAlready registered? Login here

Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionKinematicsHard2 minPYQ_2024

PhysicsHardsingle choice

A particle moving in a circle of radius $R$ with uniform speed takes time $T$ to complete one revolution. If this particle is projected with the same speed at an angle $θ$ to the horizontal, the maximum height attained by it is equal to $4 R$ . The angle of projection $θ$ is then given by :

Options:

Answer:

Solution:

Time period of circular motion is given by,

$\frac{2 π R}{v} = T \Rightarrow v = \frac{2 π R}{T}$

Now, maximum height $H = \frac{v^{2} \sin^{2} θ}{2 g}$

$\Rightarrow 4 R = \frac{4 π^{2} R^{2}}{T^{2}} \frac{\sin^{2} θ}{2 g}$

$\Rightarrow \sin θ = \sqrt{\frac{2 g T^{2}}{π^{2} R}}$

$\Rightarrow θ = \sin^{- 1} {(\frac{2 g T^{2}}{π^{2} R})}^{\frac{1}{2}}$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Kinematics

⏱ 2mℹ️ Source: PYQ_2024

Doubts & Discussion

Loading discussions...