Physics - Circular Motion Question with Solution | TestHub

At $v_{\max }, f$ will be limiting in nature.

$\therefore$ Balancing force in vertical direction, $N\cos 30°-mg-\mu N\cos 60°=0$
$\Rightarrow N\left[\cos 30°-\mu \cos 60°\right]=mg$
$\therefore N=\frac{800\times 10}{(0.87-0.1)}\approx 10.2\times {10}^3 \mathrm{kg} \mathrm{m} {\mathrm{s}}^{-2}$
Hence, option $1.$