Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionDynamicsMedium2 minPYQ_2021

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A particle is moving with uniform speed along the circumference of a circle of radius $R$ under the action of a central fictitious force $F$ which is inversely proportional to $R^{3}$ . Its time period of revolution will be given by :

Options:

Answer:

Solution:

$F \propto \frac{1}{R^{3}}$

$\frac{K}{R^{3}} = m ω^{2} R$

$ω^{2} = \frac{K}{m} \times \frac{1}{R^{4}}$

${(\frac{2 π}{T})}^{2} = \frac{K}{m} \times \frac{1}{R^{4}}$

$T^{2} \propto R^{4}$

$T \propto R^{2}$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Dynamics

⏱ 2mℹ️ Source: PYQ_2021

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