A point on the periphery of a rotating disc has its acceleration vector making an angle $30 °$ with the velocity vector. Then, the ratio of the magnitude of centripetal acceleration to the tangential acceleration is
Options:
Answer:
C
Solution:
$\tan θ = \frac{a_{N}}{a_{t}}$

Question

A point on the periphery of a rotating disc has its acceleration vector making an angle $30 °$ with the velocity vector. Then, the ratio of the magnitude of centripetal acceleration to the tangential acceleration is

Options:

Answer:

C

Solution:

$\tan θ = \frac{a_{N}}{a_{t}}$

TestHub · Accepted Answer

tan ⁡ θ = a N a t

Physics - Circular Motion Question with Solution | TestHub

Options:

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