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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

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A car turns a corner on a slippery road at a constant speed of $10 m s^{- 1}$ . If the coefficient of friction is $0.5$ , the minimum radius of the arc in $m$ in which the car turns is

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Answer:

Solution:

Given, $v = 10 m s^{- 1}$ , $μ = 0 .5$

We know that $v_{m a x} = \sqrt{μ g R}$

On squaring both sides, we get

$R = \frac{v^{2}}{μ g}$

$= \frac{100}{0.5 \times 10} = 20 m$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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