Start Free Mock LoginAlready registered? Login here

Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle of mass $m$ is fixed to one end of a light spring of force constant $k$ and unstretched length $l$ . The system is rotated about the other end of the spring with an angular velocity $ω$ , in gravity free space. Then increase in length of the spring will be:

Options:

Answer:

Solution:

Let $x$ be increase in length of the spring. The particle would move in a circular path of radius $(l + x)$ . Centripetal force = force due to the spring

$m (l + x) ω^{2} = k x$

$∴ x = \frac{m ω^{2} l}{k - m ω^{2}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...