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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A stone of mass $1 kg$ is tied to a string $4 m$ long and is rotated at a constant speed of $40 m s^{- 1}$ in a vertical circle. The ratio of the tension at the top and the bottom is

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Answer:

Solution:

$T_{t o p} = \frac{m v^{2}}{r} - m g$ ...(i)

$T_{b o t t o m} = \frac{m v^{2}}{r} + m g$ ...(ii)

$\frac{T_{t o p}}{T_{b o t t o m}} = \frac{\frac{v^{2}}{r} - g}{\frac{v^{2}}{r} + g}$

$= \frac{400 - 10}{400 + 10} = \frac{390}{410} = \frac{39}{41}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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