Physics - Circular Motion Question with Solution | TestHub

Here,$\mu =\text{0.5}$

r = 5 m, g = 10 m s^-2

The friction force provides the centripetal force

$\therefore \frac{{\text{mv}}^2}{\text{r}}=\mu \text{mg}$or${\text{v}}^2=\mu \text{rg}$

or$\text{v}=\sqrt{\mu \text{rg}}=\sqrt{\left(\text{0.5}\right)\left(5\text{ m}\right)\left(10{\text{ m s}}^{-2}\right)}$

$=5{\text{ m s}}^{-1}$

As$\text{v}=\text{r}\omega$or$\omega =\frac{\text{v}}{\text{r}}=\frac{5{\text{ m s}}^{-1}}{5\text{ m}}=1{\text{ rad s}}^{-1}$