In a circular motion of a particle, the tangential acceleration of the particle is given by a t = 9 m s - 2 . The radius of the circle is 4 m . The particle was initially at rest. Time after which tot

Question

In a circular motion of a particle, the tangential acceleration of the particle is given by $a_{t} = 9 m s^{- 2}$ . The radius of the circle is $4 m$ . The particle was initially at rest. Time after which total acceleration of the particle makes an angle of $45 °$ with the radial acceleration is

Options:

Answer:

B

Solution:

At $45 °$ , $a_{t} = a_{r} = 9$

$\frac{v^{2}}{r} = \frac{v^{2}}{4} = 9$

$v = 6 m s^{- 1}$

$6 = 0 + 9 t$

$t = \frac{2}{3} s$ .

TestHub · Accepted Answer

At 45 ° , a t = a r = 9 v 2 r = v 2 4 = 9 v = 6 m s - 1 6 = 0 + 9 t t = 2 3 s .

Physics - Circular Motion Question with Solution | TestHub

Options:

Doubts & Discussion