A circular disc with a groove along its diameter is placed horizontally. A block of mass 1 kg is placed as shown. The coefficient of friction between the block and all surfaces of groove in contact is

Question

A circular disc with a groove along its diameter is placed horizontally. A block of mass $1 kg$ is placed as shown. The coefficient of friction between the block and all surfaces of groove in contact is $μ = 2/5$ . The disc has an acceleration of $25 m / s^{2}$ . Find the acceleration of the block with respect to disc.

TestHub · Accepted Answer

Normal reaction in vertical direction N 1 ​ = m g Normal reaction from side to the groove N 2 ​ = ma sin 3 7 ∘ Therefore, acceleration of block with respect to discs a r ​ = m ma cos 3 7 ∘ − μ N 1 ​ − μ N 2 ​ ​ Substituting the values we get, a r ​ = 10 m / s 2

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