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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousMedium2 minPYQ_2005

PhysicsMediumsingle choice

A stone tied to the end of a string of 1 $m$ long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone?NEET 2005

Options:

Answer:

Solution:

$a = \frac{v ^{2}}{r} = ω^{2} r = 4 π^{2} n^{2} r = 4 π^{2} (\frac{22}{44})^{2} \times 1 = π^{2} m / s^{2}$ and its direction is always along the radius and towards the centre.

Stream:NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2005

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