A particle moves along a circle ( π 20 ) m with constant tangential acceleration. If the velocity of the particle is 80 m / s at the end of the second revolution after after motion has begun, the ta

Question

A particle moves along a circle ( π 20 ​ ) m with constant tangential acceleration. If the velocity of the particle is 80 m / s at the end of the second revolution after after motion has begun, the tangential acceleration is:NEET 2003

TestHub · Accepted Answer

From question ​ r = π 20 ​ m , v = 80 m / s ∴ θ = 2 revolutions = 2 × 2 π = 4 π rad ∴ ω 2 = ω 0 ​ 2 + 2 α θ ∴ ω 2 = 2 α θ … ( i ) since ω 0 ​ = 0 Since α = r a ​ and ω = r V ​ ​ Putting these values in eq. (i) ​ r 2 V 2 ​ = r 2 a θ ​ ⇒ a = 2 r θ V 2 ​ = 2 × ( π 20 ​ ) × 4 π 80 × 80 ​ = 40 m / s 2 ​

Physics - Circular Motion Question with Solution | TestHub

Options:

Doubts & Discussion