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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCollisionMedium2 minQB

PhysicsMediumsingle choice

Two blocks of masses m and M are moving with speeds $v_{1}$ and $v_{2} (v_{1} > v_{2})$ in the same direction on the frictionless surface respectively, M being ahead of m. An ideal spring of force constant k is attached to the backside of M (as shown). The maximum compression of the spring when the block collides is:

Options:

Answer:

Solution:

At maximum compression the blocks move together momentarily, so their initial relative kinetic energy is stored in the spring.

$μ = \frac{m M}{m + M}$

$\frac{1}{2} μ (v_{1} - v_{2})^{2} = \frac{1}{2} k x^{2}$

$x = (v_{1} - v_{2}) \frac{m M}{( m + M ) k}$

Option C.

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Collision

⏱ 2mℹ️ Source: QB

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