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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassImpulse momentum theoremMedium2 minQB

PhysicsMediumsingle choice

Passage / Comprehension

Two identical particles each of mass 4 kg are placed together at the edge of a tall cliff. They are joined by an inextensible string of negligible mass. One of the particles is projected with a speed of $103 m/s$ at 60° above the horizontal. The string becomes taut after 2 sec. (g = 10 m/s²)

The length of the string is :

Options:

Answer:

Solution:

The second particle stays at the cliff edge until the string pulls it. At t = 2 s the projectile is at $x = 103 cos 6 0^{\circ} \times 2 = 103$ , $y = 103 sin 6 0^{\circ} \times 2 - 5 (2)^{2} = 10$

$L = (103)^{2} + 1 0^{2} = 400 = 20 m$

Ans. (C)

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Impulse momentum theorem

⏱ 2mℹ️ Source: QB

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