Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassMomentum conservationMedium3 minQB

PhysicsMediumsingle choice

Passage / Comprehension

A small ball of mass 1 kg is kept in circular path of radius 1m in fixed concentric smooth horizontal ring of radius R. Angular speed of the ball in the circular motion is 1 rad/s. At a certain moment the string, which kept the ball in the circular path breaks and the ball goes off tangentially to the wall of rigid, fixed ring and bounces off elastically and again hits the ring and bounces off. After completing one round about the centre, the seventh collision takes place exactly at the position of the first collision.

Value of radius of the ring R will be

Options:

Answer:

Solution:

From the geometry of Q14, $cos β = \frac{1}{R}$ with $β = 3 0^{\circ}$ . $R = \frac{1}{c o s 3 0 ^{\circ}} = \frac{2}{3} m$ . Answer: (A)

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Momentum conservation

⏱ 3mℹ️ Source: QB

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