Physics - Center of Mass Question with Solution | TestHub

Ultimately the total loss of kinetic energy is $\frac{mM{u}^2}{2(M+m)}$

The value of the resistance force (assumed constant) offered by the wood is $F=\frac{mM{u}^2}{2d(M+m)}$

The distance covered by the bullet w.r.t. the ground before it comes to rest w.r.t. block is $\frac{dm}{M+m}$

The block moves greater distance than the bullet w.r.t. ground.