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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCollisionMedium2 min

PhysicsMediummultiple choice

A cart of mass M length L stands just at the end of a slope as shown in figure. A small block of mass m is released from rest at height h block slides on cart and comes to rest with respect to cart at the edge of cart. Friction exists between cart and block and all the surfaces are smooth. Coefficient of friction is $μ$ :-

Options:(select one or more)

Answer:

A, B, C, D

Solution:

$0 = 2 gh - μ g (1 + \frac{m}{M}) t t = \frac{2 gh M}{μ g ( m + M )} v_{cm} = \frac{m \times 2 gh + M \times 0}{m + M} Impulse = Mv_{f} - M \times 0 = Mm \frac{2 gh}{m + M}$

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Collision

⏱ 2m

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