In the shown diagram a cannon attached to a moving wedge having total mass (cannon + wedge + bullet = 3m) as shown in figure. Initially system is at rest. Cannon release bullet of mass 'm' w

Question

In the shown diagram a cannon attached to a moving wedge having total mass (cannon + wedge + bullet = 3m) as shown in figure. Initially system is at rest. Cannon release bullet of mass 'm' with speed u 'w.r.t' wedge. Find out maximum compression in spring in subsequent motion (Collision between wedge and block is perfectly elastic and initially spring is in natural length). Assume all surface are frictionless :- The block has mass 2m.

TestHub · Accepted Answer

1. Momentum of bullet + wedge (horizontal): m ( u cos θ − V ) = 2 mV ⇒ V = u cos θ /3 2. Wedge (2m) hits block (2m) elastically: velocities exchange, block moves at V . 3. Spring: 2 1 ​ ( 2 m ) V 2 = 2 1 ​ k x 2 ⇒ x = 2 m / k ​ ( u cos θ /3 ) . Answer A.

Physics - Center of Mass Question with Solution | TestHub

Options:

Doubts & Discussion

JEE Main 2028 (Class 11)