Two smooth tracks of equal length have "bumps" - A up, and B down, both of the same curvature and size. The two balls start simultaneously with the same initial speed = 3 m/s. If the speed of the ball at the bottom of the curve on track B is 4 m/s, then the speed of the ball at the top of the curve on track A is

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Energy drop on track B : 4 2 = 3 2 + 2 g h ⇒ 2 g h = 7 . On track A the same bump goes up: v 2 = 3 2 − 2 g h = 9 − 7 = 2 , so v = 2 ​ < 2 m / s . Answer: (C)

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