A block of mass 1 kg is resting on a rough horizontal surface with coefficient of friction 0.2 . If an impulse $(10 \hat{i} - 10 \hat{j}) N$ -s is given to block then the distance travelled by the block till it stops (after the impulse)
is :

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∫ Ndt = 10 Ns ∫ fdt = μ ∫ Ndt = 0.2 × 10 = 2 Ns 10 − 2 = 1 v ⇒ v = 8 m / s s = 16 m

Physics - Center of Mass Question with Solution | TestHub

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JEE Main (2028)

JEE Main + Advanced (1 year 12th class)