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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassMomentum conservationMedium3 minQB

PhysicsMediumsingle choice

A ball of mass 100 gm falls from 5m on a floor. After each collision, the speed of ball is halved. The total momentum transferred by the ball to the ground is (in kg-m/s) :-

Options:

Answer:

Solution:

Impact speed $v = 2 g h = 2 \times 10 \times 5 = 10 m / s$ ; rebound speeds 5, 2.5, 1.25, . . . Each bounce transfers $m (u + \frac{u}{2}) = \frac{3}{2} m u$ : total $= \frac{3}{2} (0.1) (10 + 5 + 2.5 + \dots)$ . $= 0.15 \times \frac{10}{1 - \frac{1}{2}} = 0.15 \times 20 = 3 kg - m / s$ . Answer: (A)

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Momentum conservation

⏱ 3mℹ️ Source: QB

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