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PhysicsCenter of MassImpulse momentum theoremMedium2 minQB

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Passage / Comprehension

Two identical particles each of mass 4 kg are placed together at the edge of a tall cliff. They are joined by an inextensible string of negligible mass. One of the particles is projected with a speed of $103 m/s$ at 60° above the horizontal. The string becomes taut after 2 sec. (g = 10 m/s²)

Tension in the string when the second particle starts moving is :

Options:

Answer:

Solution:

At tautening, the projectile's velocity is $(53, - 5)$ ; the string direction is $(3 /2, 1/2)$ . Along-string component (5 m/s) equalises by impulse; the relative circular motion about the midpoint has $v_{re l, ⊥} = 53 m/s$ .

$T = \frac{μ v _{re l}^{2}}{L} = \frac{2 \times ( 5 3 ) ^{2}}{20} = 7.5 N$

Ans. (B)

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Impulse momentum theorem

⏱ 2mℹ️ Source: QB

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