Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCollisionHard2 minPYQ_2022

PhysicsHardsingle choice

A particle of mass $m$ is projected with velocity $v$ at an angle $θ$ with the horizontal. At its highest point, it explodes into two pieces of equal mass, one of the piece continue to move on the original trajectory, then the velocity of second piece is

Options:

Answer:

Solution:

According to the law of conservation of linear momentum at the highest point, $m v cos θ = \frac{m}{2} (v cos θ) + \frac{m}{2} v^{'}$ $\Rightarrow m v cos θ - \frac{m}{2} v cos θ = \frac{m}{2} v^{'}$ $\Rightarrow v^{'} = 2 (v cos θ - \frac{v c o s θ}{2}) = v cos θ$

Stream:BITSATSubject:PhysicsTopic:Center of MassSubtopic:Collision

⏱ 2mℹ️ Source: PYQ_2022

Doubts & Discussion

Loading discussions...