Blocks of masses m , 2 m , 4 m and 8 m are arranged in a line of a frictionless floor. Another block of mass m , moving with speed υ along the same line (see figure) collides with mass m in perfectly

Question

Blocks of masses m , 2 m , 4 m and 8 m are arranged in a line of a frictionless floor. Another block of mass m , moving with speed υ along the same line (see figure) collides with mass m in perfectly inelastic manner. All the subsequent collisions are also perfectly inelastic. By the time the last block of mass 8 m starts moving the total energy loss is p% of the original energy. Value of ‘ p ’ is close to:

TestHub · Accepted Answer

Inelastic collision mv = 16 mv 1 ΔK loss = 1 2 mv 2 − 1 2 16 M v 16 2 = 1 2 mv 2 − 1 2 M v 2 16 = 1 2 mv 2 15 16 % ΔK loss = 1 2 mv 2 15 16 1 2 MV 2 × 100 = 15 16 × 100 = 93 .75 %

Physics - Center of Mass Question with Solution | TestHub

Options:

Doubts & Discussion