A particle of mass m with an initial velocity u i ^ collides perfectly elastically with a mass 3 m at rest. It moves with a velocity v j ^ after collision, then, v is given by

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From momentum conservation mu i ^ + 0 = mv j ^ + 3 m v → ' v → ' = u 3 i ^ - v 3 j ^ From kinetic energy conservation 1 2 m u 2 = 1 2 m v 2 + 1 2 ( 3 m ) u 3 2 + v 3 2 solving v = u 2

Physics - Center of Mass Question with Solution | TestHub

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