Physics - Center of Mass Question with Solution | TestHub

For a one-dimensional elastic collision between two masses $m_1$ and $m_2$, where $m_2$ is initially at rest ($v_2=0$), the final velocity of the second mass ($v_2^{\prime }$) is given by:$$v_2^{\prime }=\frac{2m_1{v}_1}{m_1+m_2}$$ Given:$m_1=1\text{ kg},v_1=10\text{ m/s}$ $m_2=3\text{ kg},v_2=0\text{ m/s}$ Substitute the values:$$v_2^{\prime }=\frac{2\times 1\times 10}{1+3}=\frac{20}{4}=5\text{ m/s}$$ The speed of the 3 kg block after the collision is 5 m/s.