Two identical capacitor connected as shown and having initial charge Q 0 . Separation between plates of capacitor is d 0 . Suddenly left plate of upper capacitor and right plate of lower capacitor

Question

Two identical capacitor connected as shown and having initial charge $Q_{0}$ . Separation between plates of capacitor is $d_{0}$ . Suddenly left plate of upper capacitor and right plate of lower capacitor starts moving with speed V. towards left while other plate of capacitor remains fixed.

Match the quantities mentioned in List-I with their values in List-II and choose the correct answer

(V = final potential difference, V = initial potential difference)

TestHub · Accepted Answer

C 1 ​ = d 0 ​ + v t ε 0 ​ A ​ C 2 ​ = d 0 ​ − v t ε 0 ​ A ​ The charge, q , will change so that the potential remains the same, so V 2 ​ V 1 ​ ​ = 1 . ​ → C 1 ​ q 1 ​ ​ = C 2 ​ q 2 ​ ​ a s C q ​ = V → q 1 ​ + q 2 ​ = 2 Q 0 ​ ( c ha r g eco n ser v a t i o n ) → q 1 ​ + q 1 ​ [ d 0 ​ + v t d 0 ​ − v t ​ ] = 2 Q 0 ​ → q 1 ​ [ d 0 ​ + v t d 0 ​ + v t + d 0 ​ − v t ​ ] = 2 Q 0 ​ q 1 ​ = d 0 ​ Q 0 ​ ( d 0 ​ + v t ) ​ → i = d t d Q t ​ ​ ( Q f ​ = Q 0 ​ − q 1 ​ ) i = d 0 ​ Q 0 ​ v ​ ​

Physics - Capacitor Question with Solution | TestHub

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