Consider the situation shown in diagram. Both capacitors are having same capacitance C. Capacitors are initially uncharged. Switch K is closed at time = 0 & after a long time capacitors are fully char

Question

Consider the situation shown in diagram. Both capacitors are having same capacitance C. Capacitors are initially uncharged. Switch K is closed at time $= 0$ & after a long time capacitors are fully charged. Column-I represents value of r and Column-II represents charge passing through r during complete charging process. Now match the followings :

Column I	Column II
(A) $r = 0$	(P) $\frac{C V}{6}$
(B) $r = R$	(Q) $\frac{C V}{5}$
(C) $r = 2 R$	(R) $\frac{C V}{4}$
(D) $r = 3 R$	(S) $\frac{C V}{3}$
	(T) $\frac{C V}{2}$

TestHub · Accepted Answer

∫ 0 ∞ ​ l d t = 2 CV Now Let ∫ 0 ∞ ​ x d t = q and ∫ 0 ∞ ​ l 1 ​ d t = q 1 ​ Now applying loop rule 2 I 1 ​ R = rx + R ( I − I 1 ​ ) 3 I 1 ​ = R r ​ x + I 3 ∫ 0 ∞ ​ I 1 ​ d t = R r ​ ∫ 0 ∞ ​ x d t + ∫ 0 ∞ ​ l d t 3 q 1 ​ = R r ​ q + 2 CV Also ∫ 0 ​ ( I 1 ​ + x ) dt = CV ∴ q 1 ​ + q = CV

Physics - Capacitor Question with Solution | TestHub

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