Physics - Capacitor Question with Solution | TestHub

In steady state the capacitors are open, so the 5 V battery sits across the two resistor branches $2+3=5\Omega$ and $1+4=5\Omega$; each carries $I=1$ A.

Current through $1\Omega$ equals current through $3\Omega$ (both 1 A) - (C) correct.

The midpoint of the upper branch sits at $5-2(1)=3$ V, so the charge on the $2\mu F$ capacitor is $2\times 3=6\mu C$ - (A) correct.

The midpoint of the lower branch sits at $5-1(1)=4$ V, so the energy in the $4\mu F$ capacitor is $\frac{1}{2}\times 4\times 16=32\mu J$ - (B) correct.

P.d. across the $3\mu F$ capacitor is $5-4=1$ V, equal to the drop $1\times 1=1$ V across the $1\Omega$ resistor - (D) correct.