Physics - Capacitor Question with Solution | TestHub

When two charged metal spheres are put in contact, charge flows until they reach a common electric potential, $V$. The charge on a capacitor is given by $Q=CV$. Therefore, $Q_1=C_{1}V$ and $Q_2=C_{2}V$. Dividing these equations yields $\frac{Q_1}{Q_2}=\frac{C_{1}V}{C_{2}V}=\frac{C_1}{C_2}$.

The final answer is $\boxed{B}$