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PhysicsCapacitorR-C CircuitMedium2 minQB

PhysicsMediuminteger

Switch 'S' is initially closed. When steady state is reached, S is opened. Heat lost in resistor after 'S' is opened is $n \times 50 μ J . n =$ ?

Answer:

Solution:

With S closed in steady state, capacitors are fully charged and no current flows.

After S is opened, no closed conducting path remains through the resistor, so no charge passes through it.

Heat lost in resistor = 0 ⇒ n × 50 µJ = 0 ⇒ n = 0.

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:R-C Circuit

⏱ 2mℹ️ Source: QB

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