Physics - Capacitor Question with Solution | TestHub

In series combination, the equivalent capacitance is $C_{eq}=\frac{C_1{C}_2}{C_1+C_2}$.

The charge on each capacitor is the same and is given by $Q=C_{eq}V=\left(\frac{C_1{C}_2}{C_1+C_2}\right)V$.

The potential difference across capacitor $C_2$ is $V_2=\frac{Q}{C_2}$.

Substituting the value of $Q$, we get $V_2=\frac{C_{1}V}{C_1+C_2}$.