Physics - Capacitor Question with Solution | TestHub

Using the principle of conservation of energy for LC oscillations, the maximum energy stored in the capacitor is equal to the maximum energy stored in the inductor.

$\frac{1}{2}C{V}^2=\frac{1}{2}L{I}_{max}^2$

$I_{max}=V\sqrt{\frac{C}{L}}$

Substituting the given values, $C=4\times 10^{-6}\text{ F}$, $V=10\text{ V}$, and $L=10\times 10^{-3}\text{ H}$:

$I_{max}=10\times \sqrt{\frac{4\times 10^{-6}}{10\times 10^{-3}}}$

$I_{max}=10\times \sqrt{4\times 10^{-4}}$

$I_{max}=10\times 2\times 10^{-2}=0.2\text{ A}$

Answer: 0.2 A