Physics - Capacitor Question with Solution | TestHub

The potential difference $V$ across the plates of the capacitor is given by the relation:

$V=\frac{Q}{C}$

The electric field intensity $E$ between the parallel plates is uniform and is related to the potential difference $V$ and the distance $t$ between the plates as:

$E=\frac{V}{t}$

Substituting the value of $V$ in the above equation, we get:

$E=\frac{\frac{Q}{C}}{t}=\frac{Q}{Ct}$

Answer: $\frac{\mathrm{Q}}{\mathrm{Ct}}$