The circuit shown in the figure consists of a charged capacitor of capacity $3 μ F$ and a charge of $30 μ C .$ At time $t = 0,$ when the key is closed, the value of current flowing through the $5 M Ω$ resistor is $x μA .$ The value of $x$ to the nearest integer is

Question

Question diagram: The circuit shown in the figure consists of a charged capaci

Answer:

2.00

Solution:

$i_{0} = \frac{V}{R} = \frac{30 / 3}{5 \times 10^{6}} = 2 \times 10^{- 6}$
$∴ = 2.00$

TestHub · Accepted Answer

i 0 = V R = 30 / 3 5 × 10 6 = 2 × 10 - 6 ∴ = 2 . 00

Physics - Capacitor Question with Solution | TestHub

Doubts & Discussion